A capillary tube of diameter 0.20 mm is lowered vertically into water in a vessel. What should be the pressure in`N//m^(2)` to be applied on the water in the capillary tube so that water level in the tube is same as that in the vessel ? (surface tension of water is 0.07 N/m and atm pressure is `10^(5)N//m^(2))`

Options

A. `10^(3)`
B. `99xx10^(3)`
C. `100xx10^(3)`
D. `101.4xx10^(3)`

Answer

d

Explanation

Consider the meniscus of surface of water in capillary as bubble ,
`P_(i)=P_(o)+(2T)/(R)`
`=10^(5)+(2xx0.07)/(0.1xx10^(-3))`
`=10^(5)+14xx10^(2)`
`=1,00,000+1400`
`=10.1.4xx10^(3)Nm^(-2)`