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A 2kg collar is attached to a spring of ...

A 2kg collar is attached to a spring of spring constant `800 Nm^(-1)`. It slides without friction over a horizontal rod. The collar is displaced from its equilibrium position by `10.0 cm` and released. Calculate maximum acceleration of the collar.

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`a_("max") = 40 ms^(-2)`
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KUMAR PRAKASHAN-OSCILLATIONS-SECTION-B (NUMERICAL FROM TEXTUAL ILLUSTRATIONS)
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  2. A block whose mass is 2kg is fastened to a spring. The spring has a sp...

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  3. A block whose mass is 1kg is fastened to a spring. The spring has a sp...

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  4. A 5kg collar is attached to a spring of spring constant 500 Nm^(-1). I...

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  5. A 5 kg collar is attached to a spring of spring constant 500 N m^(-1)....

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  6. A 5 kg collar is attached to a spring of spring constant 500 N m^(-1)....

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  7. A 2kg collar is attached to a spring of spring constant 800 Nm^(-1). I...

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  8. A 2kg collar is attached to a spring of spring constant 800 Nm^(-1). I...

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  9. A 2kg collar is attached to a spring of spring constant 800 Nm^(-1). I...

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  13. What will be the time period of seconds pendulum if its length is doub...

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  14. For the damped oscillator, the mass m of the block is 200g, k = 90 Nm^...

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  15. For the damped oscillator, the mass m of the block is 200g, k = 90 Nm^...

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  16. For the damped oscillator, the mass m of the block is 200g, k = 90 Nm^...

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  17. For the damped oscillator, the mass m of the block is 400g, k = 120 Nm...

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  18. For the damped oscillator, the mass m of the block is 400g, k = 120 Nm...

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  19. For the damped oscillator, the mass m of the block is 400g, k = 120 Nm...

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  20. A oscillator of mass 100g executes damped oscillation. When it complet...

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