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The displacement of a simple harmonic os...

The displacement of a simple harmonic oscillator is given by `y= 0.40 sin (440t +0.61)`. For this, what are the value of angular frequency.

Text Solution

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Comparing `y= 0.40 sin (440t + 0.61)" with " y= A sin (omega t+ phi)`
Angular frequency `omega = 440 rad s^(-1)`
Frequency `f= (omega)/(2pi)`
`=(440xx7)/(2xx22)= 70 Hz`.
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