The frequency of oscillation of a mass m suspended by a spring is 'v'. If mass is cut to one fourth then what will be the frequency of oscillation?

Explanation

The frequency of oscillation of a mass suspended by a spring
`v = (1)/(2pi) sqrt((k)/(m))`
`therefore v propto (1)/(sqrt(m))`
`therefore (v_2)/(v_1)= sqrt((m_1)/(m_2))= sqrt((m_1)/((m_1)/(4)))= sqrt(4) = 2`
`therefore v_(2) = 2v" "[therefore v_(1) = v]`.