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A force of 20 dyne applied to the end of...

A force of 20 dyne applied to the end of spring increase its length of 1mm, then force constant will be what ?

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`k= (F)/(triangle l) = (20)/(0.1) = 200 " dyne"/"cm`.
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KUMAR PRAKASHAN-OSCILLATIONS-SECTION-C (OBJECTIVE QUESTIONS)
  1. Ratio of force constants of two springs is 1 : 2 and the ratio of mech...

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  2. How many amplitudes of SHO covers the distance in the half period?

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  3. A force of 20 dyne applied to the end of spring increase its length of...

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  4. Force constant of spring is 0.5 Nm^(-1). The force necessary to increa...

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  5. If the length of second pendulum becomes (1)/(3) what will be its peri...

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  6. A person moves in sea water by terminal velocity with electronic digit...

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  7. When pendulum clock is running fast, what should be done for adjust th...

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  8. A particle executes two types of SHM. x(1) = A(1) sin omega t " and "x...

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  9. A particle executes two types of SHM. x(1) = A(1) sin omega t " and "x...

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  10. A particle executes two types of SHM. x(1) = A(1) sin omega t " and "x...

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  11. Displacement of SHM particle is x= 5 sin pi t where x is in cm. Then h...

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  12. A girl is swinging a swing in the sitting position. What will be the e...

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  13. The periodic time of SHM also measured by t= 2pi sqrt(("displacement")...

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  14. Two simple pendulums of equal length cross each other at mean position...

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  15. The amlitude of a particle executes SHM is 2 cm and the force acting a...

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  16. Can simple pendulum clock be used in an artificial satellite? Why ?

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  17. When body of mass m is suspended from a spiral spring and spring gets ...

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  18. The particle executes simple harmonic motion have periodic time 0.05s ...

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  19. At which position in the string of simple pendulum has maximum tension...

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  20. Which basic properties are needed for the system being oscillate?

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