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Force constant of spring is 0.5 Nm^(-1)....

Force constant of spring is `0.5 Nm^(-1)`. The force necessary to increase the length of 10 cm of spring will be……….. (Fill in the blank).

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`F= k triangle x`
`=0.5 xx 10xx 10^(-2)`
`= 0.05 N`.
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KUMAR PRAKASHAN-OSCILLATIONS-SECTION-C (OBJECTIVE QUESTIONS)
  1. How many amplitudes of SHO covers the distance in the half period?

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  2. A force of 20 dyne applied to the end of spring increase its length of...

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  3. Force constant of spring is 0.5 Nm^(-1). The force necessary to increa...

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  4. If the length of second pendulum becomes (1)/(3) what will be its peri...

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  5. A person moves in sea water by terminal velocity with electronic digit...

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  6. When pendulum clock is running fast, what should be done for adjust th...

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  7. A particle executes two types of SHM. x(1) = A(1) sin omega t " and "x...

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  8. A particle executes two types of SHM. x(1) = A(1) sin omega t " and "x...

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  9. A particle executes two types of SHM. x(1) = A(1) sin omega t " and "x...

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  10. Displacement of SHM particle is x= 5 sin pi t where x is in cm. Then h...

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  11. A girl is swinging a swing in the sitting position. What will be the e...

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  12. The periodic time of SHM also measured by t= 2pi sqrt(("displacement")...

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  13. Two simple pendulums of equal length cross each other at mean position...

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  14. The amlitude of a particle executes SHM is 2 cm and the force acting a...

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  15. Can simple pendulum clock be used in an artificial satellite? Why ?

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  16. When body of mass m is suspended from a spiral spring and spring gets ...

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  17. The particle executes simple harmonic motion have periodic time 0.05s ...

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  18. At which position in the string of simple pendulum has maximum tension...

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  19. Which basic properties are needed for the system being oscillate?

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  20. Can an oscillatory motion be non-periodic?

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