The periodic time of SHM on amplitude or energy or phase constant.

Write the periodic time for SHM particle.

The periodic time of SHM also measured by t= 2pi sqrt(("displacement")/("acceleration")) can we say that the time period depend on the displacement?

The particle executes simple harmonic motion have periodic time 0.05s and amplitude 4 cm, then what its maximum velocity?

Answer the following question : Time period of a particle in SHM depends on the force constant k and mass m of the particle: T=2pisqrt(m/k) . A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum?

Explain about amplitude and phase of wave.

Two particles execute SHM of same amplitude and frequency on parallel lines. They pass one another when moving in opposite directions each time their displacement is one third their amplitude. What is the phase difference between them?

If two waves of same frequency and same amplitude superimpose and produce third wave of same amplitude, then waves differ in phase by –

A particle performs SHM of amplitude A along a straight line. When it is at distance sqrt(3)/2 A from mean position, its kinetic energy gets increased by an amount 1/2momega^(2)A^(2) due to an impulsive force. Then its new amplitude becomes.

If T is the period of SHM, then write the period of kinetic and potential energy.