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SHO of periodic time 2 second starts its...

SHO of periodic time 2 second starts its oscillation from the lower end of its path of motion, its phase will be……….at time 2 second.

Text Solution

Verified by Experts

`implies theta= (2pi t)/(T)+phi = (2pi)/(2)xx2+ (3pi)/(2)`
`=2pi + (3pi)/(2) = (7pi)/(2) rad`.
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