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The displacement of a particle is repres...

The displacement of a particle is represented by the equation `y= sin^(3) omega t`. The motion is………..

A

non-periodic

B

periodic but not simple harmonic

C

simple harmonic with period `(2pi)/(omega)`

D

simple harmonic with period `(pi)/(omega)`

Text Solution

Verified by Experts

The correct Answer is:
B

Displacement of particle `y= sin^(3) omega t`
`= (3sin omega t-4sin 3 omega t)/(4)" "[therefore sin 3theta= 3sin theta- 4sin^(3)theta]`
`therefore v= (dy)/(dt)= (d)/(dt)[(3sin omega t-4sin 3omega t)/(4)]`
`therefore 4v= 3omega cos omega t -4xx3 omega cos 3 omega t`
`therefore 4v= 3omega cos omega t- 12omega cos 3 omega t`
`therefore 4(dv)/(dt)= (d)/(dt) [3omega cos omega t- 12omega cos 3omega t]`
`therefore 4a= -3omega^(2)sin omega t+ 36 omega^(2)sin 3 omega t`
`therefore a= -(3omega^(2)sin omega t- 36 omega^(2)sin 3 omega t)/(4)`
`= -omega^(2) ((3sin omega t+ 36 sin 3 omega t))/(4)`
`therefore " It is not " a propto -omega^(2)y`
Hence, motion is not SHM.
As the expression is involving sine function, hence it will be periodic.
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