The angular velocity and the amplitude of a simple pendulum is `omega` and A respectively. At a displacement x from the mean position if its kinetic energy is k and potential energy U, then the ratio of K and U is………..

Options

A. `(x^(2) omega^(2))/((A^(2)-x^(2)omega^(2))`
B. `(x^(2))/((A^(2)-x^(2))`
C. `(A^(2)-x^(2)omega^(2))/(x^(2) omega^(2))`
D. `(A^(2)-x^(2))/(x^(2))`

Answer

D

Explanation

Kinetic energy `K= (1)/(2) m omega^(2) (A^(2)-x^(2))`
and potential energy `U= (1)/(2) m omega^(2) x^(2)`
`therefore (K)/(U)= (A^(2)-x^(2))/(x^2)`.