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A simple pendulum with a bob of mass m o...

A simple pendulum with a bob of mass m oscillates from A to C and back to such that PB is H. If the acceleration due to gravity is g, then the velocity of the bob as it passes through B is………..

A

`mgH`

B

`sqrt(2gH)`

C

`2gH`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
`triangle PE = triangle KE`
`mgH= (1)/(2) mv^(2) implies v= sqrt(2gH)`
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