A particle performs a SHM with amplitude of `0.01m` and the frequency of its oscillation is 60 Hz. Find the maximum acceleration of a particle.

Options

A. `144 pi^(2) m"/"sec^(2)`
B. `144 m"/"sec^(2)`
C. `(144)/(pi^2) m"/"sec^(2)`
D. `288 pi^(2) m"/"sec^(2)`

Answer

A

Explanation

Maximum acceleration `= A omega^(2)`
`= A xx 4pi^(2) f^(2)`
`=0.01xx 4 (pi)^(2)xx (60)^(2)`
`= 144 pi^(2) m"/"s^(2)`.