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A particle executes simple harmonic moti...

A particle executes simple harmonic motion with an angular velocity and maximum acceleration of `3.5(rad)/(sec)" and "7.5(m)/(s^2)` respectively. Amplitude of the oscillation is…………..

A

`0.28m`

B

`0.36m`

C

`0.53m`

D

`0.61m`

Text Solution

Verified by Experts

The correct Answer is:
D
`a_("max")= A omega^(2)`
`implies A= (a_("max"))/(omega^2) = (7.5)/((3.5)^2)= 0.61m`
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