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Acceleration of a particle a= -bx, where...

Acceleration of a particle `a= -bx`, where x is the displacement of particle from mean position and b is constant. What is the periodic time of oscillation ?

A

`2pi sqrt(b)`

B

`(2pi)/(sqrt(b))`

C

`(2pi)/(b)`

D

`2 sqrt(((pi)/(b))`

Text Solution

Verified by Experts

The correct Answer is:
B
Comparing `a= -kx` with `a= -omega^(2)x, omega^(2)= b`
`therefore omega = sqrt(b)`
`therefore (2pi)/(T)= sqrt(b)`
`therefore T= (2pi)/(sqrt(b))`.
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