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A lift is ascending with acceleration (g...

A lift is ascending with acceleration `(g)/(3)`. Find the time period of simple pendulum of length L kept in lift.

A

`2pi sqrt((3L)/(g))`

B

`pi sqrt((3L)/(g))`

C

`2pi sqrt((3L)/(2g))`

D

`2pi sqrt((2L)/(3g))`

Text Solution

Verified by Experts

The correct Answer is:
C
`implies g_(eff)= g-(g)/(3)= (2g)/(3)`
`therefore T= 2pi sqrt((L)/(g_(eff)))= 2pi sqrt((L)/(2g"/"3))`
`=2pi sqrt((3L)/(2g))`.
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