A particle performs simple harmonic motion with speed v and acceleration a. Which of following statement is true ?

Options

A. Velocity is maximum, whereas acceleration is zero.
B. When velocity is maximum, its acceleration is maximum
C. For any value of v, the value of a is zero
D. When v is zero, a is also zero.

Answer

A

Explanation

Particle of SHM have maximum velocity at mean position. So in `v= pm omega sqrt(A^(2)-x^(2)), x=0`
`therefore v= A omega` is maximum value of velocity and in acceleration `a= -omega^(2)x, x=0, a=0`.