Home
Class 11
PHYSICS
A particle oscillate according to y= 7 s...

A particle oscillate according to `y= 7 sin 0.5 pi t`. Time taken by particle from equilibrium position to maximum displacement is……….

Text Solution

Verified by Experts

Comparing equation `y= 7sin 0.5 pi t` to general differential equation `y= A sin (omega t)`
Amplitude A= 7 unit
Angular frequency `omega = 0.5 pi` unit
`therefore (2pi)/(T) = (pi)/(2)`
`therefore T= 4` unit.
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    KUMAR PRAKASHAN|Exercise QUESTION PAPER (SECTION - B)|2 Videos

  • OSCILLATIONS

    KUMAR PRAKASHAN|Exercise QUESTION PAPER (SECTION - C)|2 Videos

  • OSCILLATIONS

    KUMAR PRAKASHAN|Exercise SECTION-F (QUESTIONS FROM MODULE SIMPLE QUESTIONS)|20 Videos

  • OBJECTIVE QUESTIONS AS PER NEW PAPER STYLE

    KUMAR PRAKASHAN|Exercise CHAPTER - 8 (Match Type questions)|5 Videos

  • PHYSICAL WORLD

    KUMAR PRAKASHAN|Exercise SECTION-E (QUESTIONS FROM MODULE)|9 Videos

Similar Questions

Explore conceptually related problems

Displacement of SHM particle is x= 5 sin pi t where x is in cm. Then how much time taken by the particle from the mean position to at maximum displacement.

A paricle performs S.H.M. with time period T . The time taken by the particle to move from half the amplitude to the maximum dispalcement is

Time period of a back performing SHM is 2 second and it can travel to and fro from equilibrium position upto maximum 5cm . At start the pendulum is at maximum displacement on right side of equilibrium position. Find displacement and time relation.

A particle executes simple harmonic motion with an amplitude A. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude form the equilibrium position is………..

A particle simple harmonic motion completes 1200 oscillations per minute and passes through the mean position with a velocity 3.14 ms^(-1) . Determine displacement of the particle from its mean position. Also obtain the displacement equation of the particle if its displacement be zero at the instant t = 0 .

A particle move a distance x in time t according to equation x = (t + 5)^-1 . The acceleration of particle is proportional to.

Time taken by the particle to reach from A to B is t . Then the distance AB is equal to

Displacement (in metre) of a particle varies with time (in second) is given as y(t) = 4t ^(2) - 16t +5. Time taken by the particle to come to rest is…….

(a) The position of a particle moving along the x-axis depends on the time according to equation. x=(3t^(2)-t^(3)) m. At what time does the particle reaches its maximum x-position? (b) What is the displacement during the first 4s.

A particle executes SHM on a straight line path. The amplitude of oscillation is 2 cm. When the displacement of the particle from the mean position is 1 cm, the magnitude of its acceleration is equal to that of its velocity. Find the time period, maximum velocity and maximum acceleration of SHM.