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The position-time graph of a body of mas...

The position-time graph of a body of mass 0.04 kg. Suggest a suitable physical context for this motion. What is the time between two consecutive impulses received by the body? What is the magnitude of each impulse ?

Text Solution

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Initial velocity `v_(1) =` slope of `bar(OA)`
`=((2-0)/(2-0)) `
Final velocity `v_(2) `= slope of `bar(AB)`
`=(0-2)/( 4-2) = 1 cms^(-1)`
`v_(2) = - 1 xx 10^(2) ms^(-2)` Now impulse of force
`Delta p = m(v _(1) - v_(2))`
` = 0.04 (1xx 10^(2) = (-1 xx 10^(2))`
`= 8 xx 10^(-4) Ns`
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Knowledge Check

  • If velocity-time graph for a body in motion is a straight line parallel to time axis, what type of motion is the body performing ?

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    B
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