A vehicle of 100 kg is moving with velocity of 5 m/s. How much force will be required to stop in `1/10` sec ?

Explanation

`m= 100 kg`
`v_(0) = 5 m//s`
`t = (1)/(10) sec`
`=100 (-50) `
`=- 5000 N`
`a= (v-v_(0))/( t ) = (6-5)/((1)/(10))`
`=-50`
Negtive sign indicate retarding force