In the previous problem (3), the magnitude of the momentum transferred during the hit is

Options

A. zero
B. 0.75 kg `-ms^(-1)`
C. 1.5 kg `-ms^(-1)`
D. 14 kg `-ms^(-1)`

Answer

C

Explanation

`1.5 kg - m s^(-1)`
As proved in above solution
`Delta p =- [ 0.9 hat(j ) + 1.2 hat(j )]`
Magnitude =`|Delta p |= sqrt ((0.9)^(2) + (1.2)^(2))`
`= 1.5 kg m//s`