When 20 N force is applied on a body of mass m, acceleration 8.0 `ms^(2)` is produced in it. The same force when applied on a body of mass m', acceleration of 24 `ms^(2)` is produced. What will be acceleration produced by the same force applied on these two bodies tied togather......

Options

A. `2 ms^(-2)`
B. `8 ms^(-2)`
C. `6 ms^(-2)`
D. `4 ms^(-2)`

Answer

C

Explanation

`m= (F )/(a ) = (20)/( 8) = 2.5 kg`
Now m`=(F ) /( a ) = (20)/( 24) = 0.8333kg`
Acceleratin produced when both the bodies are tied up .
`a = (F ) /( (m+ m)) = (20)/(2.5 + 8.833 ) = 6.006 m//s^(2)`