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A block of mass 15 kg is lying on an inc...

A block of mass 15 kg is lying on an inclined plane of angle `30^(@)`. In order to make it move upward along the slope with an acceleration 25 `cms^(2)`, a horizontal force of 200 N is required to be applied on it. Then the frictional force on the block i s (g = 9.8 ms 2)

A

95.95 n

B

134 n

C

99.70 n

D

90 n

Text Solution

Verified by Experts

The correct Answer is:
C

From the figure if the block is moving upward along the slope with an acceleration `a_(x )` them `Sigma F_(x ) ne 0 ` but `Sigma F_(x ) = ma_(x )`
`200 xx 0.866-f -15 xx 9.8 xx (1)/(2) =15 xx 0 .25`
`173.2 -f -73.5 = 3.75`
`:. , 95 . 95 N=f`
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  • A block of mass 20 kg is lying on an inclined plane of angle 30^(@) . In order to make it move upward along the slope with an acceleration of 25 cm/ s^(2) , a horizontal force of 400 N is required to be applied on it. (i) Frictional force on the block is .......N. (ii) Co-efficient of kinetic friction i s .........

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