If linear momentum of a body is increased by 0.5% its kinetic energy increases b y ..

Options

A. 0.1
B. 0.01
C. 0.02
D. 0

Answer

B

Explanation

`1 %`
`k= (p^(2))/( 2m )` where 2 m is equal
`k= P^(2)`
`(Delta k )/( k ) = (2Delta p )/( p )`
`(Delta k )/( k ) xx 100 = 2xx (Delta p ) /( p ) xx 100`
`=2 xx 0.5 %`
`=1.0 %`