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Two masses m(1) = 4.8 kg and m(2) = 5 kg...

Two masses `m_(1)` = 4.8 kg and `m_(2)` = 5 kg tied to a string are hanging over a light frictionless pully. What is the acceleration of masses when they are free to move ?

A

0.2 `m//s^(2)`

B

9.8 `m//s^(2)`

C

5 `m//s^(2)`

D

4.8 `m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

Suppose the acceleration of composite system is a
`m_(2) g - T =m_(2) a ` and
Adding these two equations
`(m_(2)-m_(1)) g = (m_(1) =m_(2)) a`
`a= ((m_(2) - m_(1))/(m_(1) + m_(2))) g `

`=((5-4.8)/( 5+ 4.8)) 9.8`
`=(0.2)/(9.8) xx 9.8`
`a= 0.2 m//s^(2)`
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