A player caught a cricket ball of m ass 150 g moving at a rate of 20 `m //s^(- 1)` . If the catching process is com pleted in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to .....

Options

A. 0.3 N
B. 3 N
C. 30 N
D. 300 N

Answer

C

Explanation

The force of the blow exerted by the ball on the hand of the player = the change in momentum of the ball
`F= m(v_(1) -v_(2))/( t )`
`=(0.15 (20 - 0))/( 0.1) `
`F= 30 N`
`m =150 g = 0.150 kg`
`v_(1) = 20 m//s`
`v_(2) =0`
`t=0.1s`