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On earth, the value of G = 6.67 xx 10^(-...

 On earth, the value of `G = 6.67 xx 10^(-11) Nm^(2)// kg^(2)` . What is its value on the moon ?

Text Solution

Verified by Experts

`implies`  The value of G is the same everywhere in the universe. So, it is `6.67 xx 10^(-11) Nm^(2) //kg^(2)` on moon.
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The value of G on the surface of the earth is 6.673 xx 10^(-11) N m^2kg^(-2) . What is its value on the moon ?

If in a system the force of attraction between two point masses of 1kg each situated 1km apart is taken as a unit force and is called newton(newton written in reverse order) If G = 6.67 xx 10^(-11) N-m^(2)kg^(-2) in \SI units, the relation of newton and newton is

Knowledge Check

  • A particle of mass 10 g is kept of the surface of a uniform sphere of mass 100 kg and radius 10 cm. Find the work to be done against the gravitational force between them to take the particle far away from the sphere. (Take G = 6.67 xx 10^(-11) Nm^(2)//kg^(2) ?

    A
    `6.67 xx 10^(-9) J`
    B
    `6.67 xx 10^(10) J`
    C
    `13.34 xx 10^(-10) J`
    D
    `3.33xx 10^(-10) J`

  • At what height from the surface of earth the gravitation potential and the value of g are - 5.4 xx 10^(+7) JKg^(-2) and 6.0 ms^(-2) respectively ? Take the radius of earth as 6400 km.

    A
    1600 km
    B
    1400 km
    C
    2000 km
    D
    2600 km

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    If the value of universal gravitational constant is 6.67xx10^(11) Nm^2 kg^(-2), then find its value in CGS system.

    The time period of revolution of moon around the earth is 28 days and radius of its orbit is 4xx10^(5) km. If G=6.67xx10^(-11) Nm^(2)//kg^(2) then find the mass of the earth.

    G = 6.67xx10^(-11) N m^(2)(kg)^(-2) = ………. (cm)^(3)s^(-2)g^(-1) .

    A satellite of mass 200 kg revolves around the surface at the height of 1000 km. Find (1) Bindinig energy (2) Escape speed of the satellite. Mass of earth is 6 xx 10^(24) kg Radius of earth = 6400 km and G = 6.67 xx 10^(-11) Nm^(2)//kg^(2) ?.

    At what height from the surface of earth the gravitation potential and the value of g are - 5.4 xx 10^(7) J kg^(-2) and 6.0 ms^(-2) respectively ? Take the radius of earth as 6400 km :

    Give the order of the following : (a) 1 (b) 1000 (c ) 499 (d) 500 (e) 501) (f) 1 AU (1.496 xx 10^(11) m) (g) 1 Å (10(-10)m ) (h) Speed of light (3.00 xx 10^(8) m//s) (i) Gravitational constant (6.67 xx 10^(-11) N-m^(2)//kg^(2)) (j) Avogadro constant (6.02 xx 10^(23) mol^(-1)) (k) Planck's constant (6.63 xx 10^(-34) J-s) (l) Charge on electron (1.60 xx 10^(-19) C) (m) Radius of H - atom (5.29 xx 10^(-11)m) (n) Atmospheric pressure (1.01 xx 10^(5) Pa) (o) Mass of earth (5.98 xx 10^(24)kg) (p) Mean radius of earth (6.37 xx 10^(6)m)

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