The escape velocity on the surface of ea...

The escape velocity on the surface of earth is 11.2 km/s. What will be its value on a planet having double the radius and eight times the mass of earth?

Text Solution

Verified by Experts

`implies v_p/v_e=sqrt((2GM_e)/R_p)xx sqrt((R_e)/(GM_e))=sqrt(M_p/M_exxR_e/R_p)`
`v_p/v_e=sqrt(8xx1/2)=sqrt4 =2`
`:. v_p=2v_e=2 (11.2km//s)= 22.4 (km)/s`

Topper's Solved these Questions

GRAVITATION
KUMAR PRAKASHAN|Exercise Section - D NCERT Exemplar Solutions (Multiple Choice Questions (MCQs))|15 Videos
GRAVITATION
KUMAR PRAKASHAN|Exercise Section - D NCERT Exemplar Solutions (MIultiple Choice Questions (More than one options) )|1 Videos
GRAVITATION
KUMAR PRAKASHAN|Exercise Section - C Objective Questions (VSQs) (Answer the following questions In short :)|11 Videos
LAW OF MOTION
KUMAR PRAKASHAN|Exercise (QUESTION PAPER) SECTION-D|1 Videos

Similar Questions

Explore conceptually related problems

The escape velocity of the surface of earth is 11.2 km/s. What would be the escape velocity of the surface of another planet of the same mass but (1^(th))/4 times the radius of the earth ?

The escape velocity from the surface of earth is v_e . The escape velocity from the surface of a planet whose mass and radius are 3 times those of the earth will be ...........

The escape velocity for the earth is 11.2 km / sec . The mass of another planet is 100 times that of the earth and its radius is 4 times that of the earth. The escape velocity for this planet will be

Escape velocity for earth surface is 11 km/s. If the radius of any planet is two times the radius of the earth but average density is same that of earth, then the escape velocity at the planet will be ........

Escape velocity of a body from the surface of earth is 11.2km/sec. from the earth surface. If the mass of earth becomes double of its present mass and radius becomes half of its present radius then escape velocity will become

The acceleration due to gravity on the surface of moon is 1.7 m s^(-2) . What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s ? (g on the surface of earth is 9.8 m s^(-2) )

A body weighs 63 N on the surface of the earth. What is the gravitational force on it due to the earth at a height equal to half the radius of the earth ?

A particle is thrown with escape velocity v_(e) from the surface of earth. Calculate its velocity at height 3 R :-

KUMAR PRAKASHAN-GRAVITATION-Section - C Objective Questions (VSQs)

Does speed of planet remain constant in an orbit?
Text Solution
|
What is the effect of decreasing the height of a satellite orbiting ar...
Text Solution
|
The escape velocity on the surface of earth is 11.2 km/s. What will be...
Text Solution
|
Find the kinetic energy needed to project a body of mass m from the su...
Text Solution
|
What is the escape velocity from a black hole ?
Text Solution
|
As astronaut dropped a spoon from outside spacecraft will the spoon re...
Text Solution
|
Give the name of first Indian Astronaut.
Text Solution
|
What is the frequency of oscillation of a pendulum mounted in a lift ...
Text Solution
|
Distance of two planets from the sun are 10^11 m and 10^(10) m respec...
Text Solution
|
In Bohr’s model, the atomic radius of the first orbit is r. Then, the ...
Text Solution
|
If any satellite has kinetic energy 6 xx 10^(9)J , then what its poten...
Text Solution
|
A satellite has potential energy -8 xx 10^(9)J, then what is its bindi...
Text Solution
|
The ratio between Bohr radii is
Text Solution
|
What are the factors on which escape velocity depends on ?
Text Solution
|
The period of revolution of a satellite in an orbit becomes 8 times th...
Text Solution
|
Why rocket does not have escape energy ?
Text Solution
|
Why satellite does not have escape velocity ?
Text Solution
|
What is the direction of rotation of polar satellite ?
Text Solution
|
In what direction does earth rotate ?
Text Solution
|
Why we can observed a whole surface of earth with the help of polar sa...
Text Solution
|