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If the gravitational force between two o...

If the gravitational force between two objects were proportional to `1/R` (and not as `1/R^2` ) where R is the distance between them, then a particle in a circular path (under such a force) would have its orbital speed `v_1` proportional to .........

A

`1/R^2`

B

`R^@`

C

`R^1`

D

`1/R`

Text Solution

Verified by Experts

The correct Answer is:
B
`implies (mv^2)/R = (K)/R (Fprop 1/R)`
`:. V prop R^@`
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