The earth (mass `= 6 xx 10^(24)` kg) revolves around the sun with an angular velocity of `2 xx 10^(-7)` rad/s in a circular orbit of radius `1.5 xx 10^8` km. The force exerted by the sun on the earth, in newton, is .........

Options

A. `18 xx 10^(25)`
B. zero
C. `27 xx10^(39)`
D. `36 xx10^(21)`

Answer

D

Explanation

`implies m = 6 xx 10^(24) kg , omega = 2xx 10^(-7) ` rad/s
`R = 1.5 xx 10^(11) m`
Foce exerted by Sun on the earth `= F = momega^(2) R`
`:. F = 6 xx 10^(24) xx (2 xx 10^(-7))^2 xx 1.5 xx 10^(11)`
`= 36 xx 10^(21) N`