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Escape velocity for earth surface is 11 ...

Escape velocity for earth surface is 11 km/s. If the radius of any planet is two times the radius of the earth but average density is same that of earth, then the escape velocity at the planet will be ........

A

22 km/s

B

11km/s

C

5.5 km/s

D

15.5 km/s

Text Solution

Verified by Experts

The correct Answer is:
A
`implies v_e=sqrt((2GM)/R) =R sqrt(8/3piGrho)`
`v_e prop R ` (If `rho ` is constant )
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Knowledge Check

  • The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to gravity at the surface the planet is equal to that at the surface of the earth. If the radius of the earth is R , the radius of the planet would be .......

    A
    `1/2R`
    B
    2R
    C
    4R
    D
    `1/4R`

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    A
    `9.8ms^(-2)`
    B
    `19.6ms^(-2)`
    C
    `4.9ms^(-2)`
    D
    `2.45ms^(-2)`

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    A
    `9.8 m//sec^2`
    B
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    C
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    D
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