The mass and diameter of a planet have twice the value of the corresponding parameters of earth. The acceleration on the surface of planet .........

Options

A. `9.8 m//s^2`
B. `4.9 m//s^2`
C. `980 m//s^2`
D. `19.6 m//s^2`

Answer

B

Explanation

`implies (g.)/(g) = (M.)/Mxx((R)/(R.))^2 = ((2M)/(M)) xx (R/(2R))^(2) =1/2`
`:. G. = g/2 = (9.8)/2 = 4.9 m//s^2`