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The escape velocity from the surface of ...

The escape velocity from the surface of earth is `v_e` . The escape velocity from the surface of a planet whose mass and radius are 3 times those of the earth will be ...........

A

`v_e`

B

`3v_e`

C

`9v_e`

D

`27v_e`

Text Solution

Verified by Experts

The correct Answer is:
A
`impliesv_e = sqrt((2GM)/(R) ):. v_e prop sqrt(M/R)`
If the mass and radius are 3 time those of the earth even the escape velocity remain the same .
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Knowledge Check

  • The escape velocity of the surface of earth is 11.2 km/s. What would be the escape velocity of the surface of another planet of the same mass but (1^(th))/4 times the radius of the earth ?

    A
    44.8 km/s
    B
    22.4 km/s
    C
    5.6 km/s
    D
    11.2 km/s

  • The earth is assumed to be a sphere of radius R. A platform is arranged at a height R from the surface of the earth. The escape velocity of a body from this platform is fu, where v is its escape velocity from the surface of the earth the value of f is ..........

    A
    `1/sqrt2`
    B
    `1/3`
    C
    `1/2`
    D
    `sqrt2`

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