What conclusion can you draw from the follwing observation on a resistor made of alloy manganin ?

Explanation

(1) ` R = (V)/(I) = (3.94)/(0.2) = 19.7 Omega`
(2) `R = (V)/(I) = (7.87)/(0.4) = 19.67 Omega`
(3) ` R = (V)/(I) = (11.8)/(0.6) = 19.66 Omega`
(4) `R = (V)/(I) (15.7)/(0.8) = 19.62 Omega`
`(5) R = (V)/(I) = (19.7)/(1.0) = 19.7 Omega `
`(6) R = (V)/(I) = (39.4)/(2.0) = 19.7 Omega`
`(7) R = (V)/(I) = (59.2)/(3.0) = 19.7 Omega`
`(8) R = (V)/(I) = (78.8)/(4.0) = 19.7 Omega`
`(9) R = (V)/(I) = (98.5)/(5.0) = 19.72 Omega`
(10) ` R = (V)/(I) = (118.5)/(6.0) = 19.75 Omega`
(11) `R = (V)/(I) =(138.2 )/(7.0) = 19.74 Omega`
(12) ` R = (V)/(I) = (158.0)/(8.0) = 19.75 Omega`
From above calculations we can conclude that for given alloy, its resistance R = `(V)/(I) ` remains constant and hence obeys Ohm.s law.