Two batteries of emf `epsilon_(1) and epsilon_(2) (epsilon_(2) gt epsilon_(1))` and internal resistances `r_(1) and r_(2)` respectively are connected in parallel as shown in figure.

Options

A. Two equivalent emf `epsilon_(eq)` of the two cells is between `epsilon_(1) and epsilon_(2) `, i.e . `epsilon_(1) lt epsilon_(eq) lt epsilon_(2)` .
B. The equivalent emf `epsilon_(eq)` is smaller then `epsilon_(1)`.
C. The `epsilon_(eq)` is given by `epsilon_(eq) = epsilon_(1) + epsilon_(2)` always.
D. `epsilon_(eq)` is independent of internal resistances` r_(1) and r_(2)`.

Explanation

Two equivalent emf `epsilon_(eq)` of the two cells is between `epsilon_(1) and epsilon_(2) `, i.e . `epsilon_(1) lt epsilon_(eq) lt epsilon_(2)` .
Equivalent emf of two cell with emf ` epsilon_(1) and epsilon_(2)` in parallel is given by
` epsilon_(eq) = (epsilon_(2) r_(1) + epsilon_(1)r_(2))/(r_(1) + r_(2))`
`therefore epsilon_(eq)` value will be between `epsilon_(1) and epsilon_(2)`
`therefore epsilon_(1) lt epsilon_(eq) lt epsilon_(2)`