In given circuit total power consumed is 150 W. Then value of R = ......

Options

A. 2` Omega`
B. `6 Omega`
C. `5 Omega`
D. `4 Omega`

Answer

B

Explanation

`6 Omega`
Power used in Parallel connection `P_(p) = P_(2) + P_(R)`
`therefore 150 = (V^(2))/(2) + (V^(2))/(R)`
`therefore 150 = ((15)^(2))/(2) + ((15)^(2))/(R)`
`therefore ((15)^(2))/(R) = 150 - (225)/(2) = (75)/(2)`
`therefore R = (225 xx 2)/(75)`
`therefore R = 6 Omega`