A 3 volt battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I in the circuit will be :

Options

A. 1 Amp
B. 1.5 Amp
C. 2 Amp
D. `(1)/(3)` Amp

Answer

B

Explanation

1.5 Amp
Resistance of B - C - A = `6 Omega`
`therefore ` If R is the equivalent resistance between A and B, then,
`(I)/(R) = (1)/(3) + (1)/(6) = (2 + 1)/(6) = (3)/(6)`
`therefore R = 2 Omega`
` therefore I = (V)/(R) = (3)/(2) = 1.5 ` A