In a large bullding there are 15 bulbs of 40 W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of the electric mains is 220 V. The minimum capacity of the main fuse of the building will be :

Options

A. `12 `A
B. `14`A
C. `8A`
D. `10A`

Answer

A

Explanation

`12A`
Total power = 40 `xx 15 + 100 xx 5 + 80 xx 5 + 1000`
= `600 + 500 + 400 + 1000 `
`therefore VI = 2500` W
`therefore I = (2500)/(220) = 11.36 `A
`therefore I = 12 A `