What is the current in the 40 resistor when switch `S_(1)` is open and switch `S_(2)` is closed in the given circuit ?

Options

A. `0.8 A `
B. 1.2 A
C. 1.5 A
D. 3.0 A

Answer

B

Explanation

1.2 A
By closing switch `S_(2) `, its right side part of circuit will be shorted. Hence by neglecting it.

`therefore` Current flowing through circuit,
I = `(E)/(4 + 6) = (12)/(10) = 1.2 `A
Now, current flowing through `4 Omega and 6 Omega` is same as they are in series.
`therefore ` Current flowing through `4 Omega` is 1.2 `A