Give SI unit of magnetic field from Biot-Savart law.

Explanation

According to Biot-Savart law,
`dB=mu_(0)/(4pi)Idl(sintheta)/r^(2)`
`dB=((T*m)/A)((A*m)/m^(2))`
= T (Tesla)
If we take I = I A, dl = 1 m, r = 1 m and `theta=90^(@)`,
then `dB=mu_(0)/(4pi)=(4pixx10^(-7))/(4pi)=10^(-7)` tesla
`therefore` 1 tesla = `10^(7)` dB
Thus, one tesla is `10^(7)` times the magnetic field produced by a conducting wire of length one meter and carrying current of one ampere at a distance of one meter from it and perpendicular to it.