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What is the radius of the path of an ele...

What is the radius of the path of an electron (mass `9xx10^(-31)kg` and charge `1.6xx10^(-19)C`) moving at a speed of `3xx10^(6)m//s` in a magnetic field of 6T perpendicular to it? What is its frequency ? Calculate its energy in keV. `(1eV=1.6xx10^(-19)J)`

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The correct Answer is:
r = 52 cm, v = 910 kHz, E = 47 keV
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