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When a galvanometer with a shunt is join...

When a galvanometer with a shunt is joined in an electrical circuit 2% of the total current passes through the galvanometer. Resistance of galvanometer is G. Find the value of shunt.

Text Solution

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1. Only 2 % of the total current passes through galvanometer,
`I_(G)=2%I=2/100I`
2. Shunt = `S=(GI_(G))/(I-I_(G))`
`S=(G(2/100I))/(I-2/100I)=2/100(GI)/((98))((100))/I`
`thereforeS=G/49`
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