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A circular current loop of magnetic mome...

A circular current loop of magnetic moment M is in an arbitrary orientation in an external magnetic field `vecB`. The work done to rotate the loop by `30^(@)` about an axis perpendicular to its plane is

A

MB

B

`sqrt3/2MB`

C

`(MB)/2`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B, D

Here angle between `vecMandvecB` does not change and remain same.
`W=MBcos90^(@)`
W = 0
Now if when angle between `vecBandvecM` be `theta=30^(@)`, then work done,
`W=MBcos30^(@)`
`thereforeW=sqrt3/2MB`
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