If a stationary charged particle experience an electromagnetic force then _____ .

Options

A. E = 0, B = 0
B. `Ene0,B=0orBne0`
C. `Ene0,Bne0`
D. `vecE_|_vecB`

Answer

B

Explanation

Electromagnetic force (or Lorentz force)
`F=F_(e)+F_(m)`
Initially (at t = 0) `Fne0` but `F_(m)=0`
`(becausev=0)rArrF_(e)ne0rArrEne0`
When `tgt0,Fne0`
`rArrF_(e)+F_(m)ne0`
Here `F_(e)ne0rArrF_(m)=0orF_(m)ne0`
`rArrB=0orBne0`
`rArr` Option (B) is correct.