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Magnetic field at the centre of circular...

Magnetic field at the centre of circular loop of radius R is B. Magnetic moment of this coil would be _______

A

`(BR^(3))/(2pimu_(0))`

B

`(2piBR^(3))/(mu_(0))`

C

`(BR^(2))/(2pimu_(0))`

D

`(2piBR^(2))/(mu_(0))`

Text Solution

Verified by Experts

The correct Answer is:
B
`B=(mu_(0)I)/(2R)`
`thereforeI=(2BR)/mu_(0)`
`rArr` Now `mu_(0)=IA=(2BR)/mu_(0)xxpiR^(2)" "thereforemu=(2piBR^(3))/mu_(0)`
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