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When 2.5Omega shunt is connected with 25...

When `2.5Omega` shunt is connected with `25Omega` resistance of galvanometer, what fraction of total current I would pass through galvanometer?

A

`I_(G)/I=1/11`

B

`I_(G)/I=1/10`

C

`I_(G)/I=1/9`

D

`I_(G)/I=2/11`

Text Solution

Verified by Experts

The correct Answer is:
A

`I_(G)=IxxS/(S+G)`
= `Ixx2.5/(2.5+25)`
`thereforeI_(G)/I=2.5/27.5=1/11`
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