The resistance of galvanomenter is G and its current capacity is `I_(g)`. To increase the current capacity by 'n' times, the required value of shunt is ______ .

Options

A. `G/(n-1)`
B. `(I_(g)*G)/(n-1)`
C. `(nG)/(n-1)`
D. `(I_(g)*G)/(I-n*I_(g))`

Answer

A

Explanation

`I=nI_(g)`
`S=(I_(g)G)/(I-I_(g))=(I_(g)G)/(nI_(g)-I_(g))=G/(n-1)`