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Resistance of ammeter made by combinatio...

Resistance of ammeter made by combination of `20Omega` galvanometer and `2Omega` shunt is ______

A

`0.18Omega`

B

`1.8Omega`

C

`18Omega`

D

`22Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
If resistance of ammeter is R, then `1/R=1/G+1/S`
`thereforeR=(GS)/(G+S)=(20xx2)/(20+2)=40/22~~1.8Omega`
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