A conducting rod of mass 1 kg and length 1 m is suspended by two strings, so as to remain horizontal. If 2T horizontal magnetic field is applied perpendicular to the length of the rod then what amount of current should be passed through this rod to remove tension in two strings ? (Take g = `10ms^(-2)`)

Options

A. 0.5A
B. 1.5A
C. 5A
D. 15A

Answer

C

Explanation

Situation given in the statement is depicted in following figure.

For equilibrium of considered rod,
`2T+F_(m)=W`
`thereforeF_(m)=W" "(because"As per the statement "2T=0)`
`thereforeIlBasin90^(@)=mg`
`thereforeI=(mg)/(lB)=(1xx10)/(1xx2)=5A`