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Unpolarised light is incident on a plane...

Unpolarised light is incident on a plane glass surface. What would be the angle of incidence so that the reflected and refracted rays are perpendicular to each other.

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Here, reflected and refracted light rays are given perpendicular and so angle of incidence (1) must be equal to polarising angle or Brewster angle shown by symbol `theta_(p)`. Now, according to Brewsters. law,
`tantheta_(P)=mu`
`:.tantheta_(P)=1.5`
`("":."Here "mu-mu_(ga)-(mu_(g))/(mu_(a))=(1.5)/(1)=1.5)`
But `tan(56^(@)19.)=1.5003~~1.5`
`impliestheta_(P)=56^(@)19.`
Note: Here if `theta_(P)` is required only in degree then
`theta_(P)=56^(@)+19.=56^(@)+((19)/(60))^(@)`
`=56^(@)+(0.32)^(@)`
`=(56.32)^(@)`
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