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Two waves with wavelength lamda have pha...

Two waves with wavelength `lamda` have phase difference of 60° at the point of superposition. Find path difference between them.

Text Solution

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According to Malus. law, `I=I_(0)cos^(2)theta`
`:.(I)/(I_(0))=cos^(2)theta=cos^(2)(60^(@))=(0.5)^(2)=0.25=(1)/(4)` but `IpropE^(2)`
`(E^(2))/(E_(0)^(2))=(1)/(4)implies(E)/(E_(0))=(1)/(2)`
`:.(E_(0))/(E)=(2)/(1)`
`:.(E_(0)-E)/(E_(0))=(E_(0)-E_(0//2))/(E_(0))`
`:.(E_(0)-E)/(E_(0))xx100%`
`=(1)/(2)xx100%`
`=50%`
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